Answer:
Yes, PQR ~ TSV with a scale of 1 : [tex]\sqrt{3}[/tex]
Step-by-step explanation:
Yes the triangles are congruent for the statement given in option C
The scale 1 : [tex]\sqrt{3}[/tex] shows that the side lengths are proportional
PQ/TS = QR/SV
3[tex]\sqrt{3}[/tex]/6/[tex]\sqrt{3}[/tex] and that's simplified as 1/[tex]\sqrt{3}[/tex]
