2. What is the area of rhombusABCD? (Assume the diagonals of rhombus ABCD are equal).


2 What Is The Area Of RhombusABCD Assume The Diagonals Of Rhombus ABCD Are Equal class=

Sagot :

Answer:

A=pq/2

=4.25·4.25/2

=9.03125

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Diagonal of rhombus bisect each other.

d₁ = AC = 4.25*2 = 8.5 cm

d₂ = 8.5  {Given diagonals are equal}

Area of rhombus = [tex]\frac{d_{1}*d_{2}}{2} \ where \ d_{1} \ and \ d_{2} \ are \ diagonals[/tex]

                            [tex]=\frac{8.5*8.5}{2}\\\\= \frac{72.25}{2}\\\\= 36.125 \ cm^{2}[/tex]