Answer:
[tex]\frac{2\sqrt[3]{22} }{7}[/tex]
Step-by-step explanation:
We are asked to find the cube root of [tex]\sqrt[3]{\frac{176}{343} }[/tex]
To solve, let's start with the radical rule of having a fraction within a cuberoot, which is cubing both the numerator and denominator :
[tex]\frac{\sqrt[3]{176} }{\sqrt[3]{343} }[/tex]
Simplify both equations for the answer:
[tex]\sqrt[3]{176} = 2\sqrt[3]{22}[/tex]
[tex]\sqrt[3]{343} = 7[/tex]
[tex]\frac{2\sqrt[3]{22} }{7}[/tex]
