Sagot :
Answer:
Consider the following identity:
- a³ - b³ = (a + b)(a² - ab + b²)
Let a = 2, b = 1/2
- (2 + 1/2)(2² - 2*1/2 + 1/2²) =
- 2³ - (1/2)³ =
- 8 - 1/8
Use the algebraic identity given below
[tex]\boxed{\sf a^3-b^3=(a+b)(a^2-ab+b^2)}[/tex]
[tex]\\ \sf\longmapsto (2+\dfrac{1}{2})(2^2-1+\dfrac{1}{4})[/tex]
[tex]\\ \sf\longmapsto (2+\dfrac{1}{2})(2^2-2\times \dfrac{1}{2}+\dfrac{1}{2}^2)[/tex]
- Here a =2 and b=1/2
[tex]\\ \sf\longmapsto 2^3-\dfrac{1}{2}^3[/tex]
[tex]\\ \sf\longmapsto 8-\dfrac{1}{8}[/tex]