Sagot :
Answer:
[tex]4(6a + 2b^2) - 1/3 (27b^2 - 15a)[/tex]
a = -2
b = 3
[tex]4\left(6\left(-2\right)+2^2\right)-1/3\left(27\left(3\right)^2-15\left(-2\right)\right)[/tex]
Follow the PEMDAS order of operations:-
- Parentheses
- Exponents
- Multiplication or Division
- Addition or Subtraction
[tex]4\left(6\left(-2\right)+2^2\right)[/tex]
calculate within Parentheses
[tex]6\left(-2\right)+2^2[/tex]
[tex]2^{2} =4[/tex]
[tex]6(-2)=-12[/tex]
Add:-
[tex]-12+4=-8[/tex]
[tex]4\left(-8\right)-1/3\left(27\left(3\right)^2-15\left(-2\right)\right)[/tex]
calculate within Parentheses:-
[tex]27\left(3\right)^2-15\left(-2\right)[/tex]
[tex](3)^{2} =9[/tex]
[tex]27*9=243[/tex]
[tex]243-15\left(-2\right)[/tex]
[tex]15(-2)=-30[/tex]
[tex]243-\left(-30\right)[/tex]
[tex]=273[/tex]
[tex]4\left(-8\right)-1/3\cdot \:273[/tex]
Multiply:-
[tex]4\left(-8\right)=-32[/tex]
[tex]-32-1/3\cdot \:273[/tex]
[tex]1/3*273=91[/tex]
[tex]=-32-91[/tex]
[tex]=-123[/tex]
OAmalOHopeO