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A block of ice is floating in a cup of water. It is 0.5 cm above the water surface and its length
and width are 2cm each. Given that the density of ice is 900 kgm 3 and the density of the
water is 1000 kgm3, find the volume of the ice block.
0.5 cm
d cm
2 cm
2 cm

Sagot :

Answer:

Let the volume of the cube be V and the fraction of cube outside water be f.

Thus, volume of ice inside water = volume of water displaced =(1−f)V

Under equilibrium,

Weight of ice = Weight of water displaced

⟹Vρ

ice

g=(1−f)Vρ

water

g

⟹(1−f)=

10

9

⟹f=

10

1

Thus, the percentage of volume outside water =10%

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