Answer:
F an amazing result.
Step-by-step explanation:
I'm sure I didn't do this the way it was intended, but I think I got it right.
First of all, we have to agree that CAB is marked as a right angle. If you do not agree, leave a note.
Step One
Find the length of AC
BC = 16
AB = 10
AC^2 = BC^2 - AB^2
AC^2 = 16^2 - 10^2
AC^2 = 256 - 100
AC^2 = 156
AC = SQRT(156)
AC = SQRT(4*13 * 3)
AC = 2 SQRT(13)
Step Two
Find the height (AD)
There are two ways to find the area of the large triangle ABC
Area = 1/2 * 16 * AD and
Area = 1/2 AC * 10 The two legs.
Since these areas must be equal, equate them. You are looking for AD
16 * AD = 2*sqrt(39) * 10 Divide by 16
AD = 20* sqrt(39)/16
AD = 5 * sqrt(39) / 4
Step 3
Find x or DB
DB^2 = 10^2 - [(5 *sqrt(39)/4]^2
DB^2 = 100 - 25*39/16
DB^2 = 100 - 60.9375
DB^2 = 39.0625
DB = SQRT(39.0625)
DB = 6 1/4
6 1/4 is the same thing as 25/6 which is F