Answer:
D. Multiple zero is 3; multiplicity is 2
Step-by-step explanation:
f(x) = (x-3)(x-3)(x+5)
0 = (x-3)(x-3)(x+5)
x = -5,3,3
notice 3 shows up twice. That would be your answer...So D.
Answer:
Multiple zero is 3; multiplicity is 2
Step-by-step explanation:
f(x) = (x - 3)(x - 3)(x + 5)
Rewriting
f(x) = (x - 3)^2(x + 5)
Setting equal to zero
0 = (x - 3)^2(x + 5)
Using the zero product property
(x-3)^2 = 0 x+5 = 0
x-3 = 0 x= -5
x=3 x-5
Since x-3 was squared, the multiplicity is 2
