Answer:
Step-by-step explanation:
let the height of the room(h) = x
Length(l) = 3*x = 3x
length = 2 * breadth
breadth(b) = length /2 = 3x/2
Cost of whitewashing the 4 walls = ₹ 7200
Area of 4 walls = 7200 ÷ 50 = 144 m² ------(I)
Area of walls = 2lh + 2bh
= 2*3x*x + 2 *[tex]\frac{3x}{2}[/tex] * x
= 6x² + 3x²
= 9x²
9x² = 144 {From (I)}
x² = 144/9
x² = 16
x = [tex]\sqrt{16}=\sqrt{4*4}[/tex]
x = 4 m
height = 4 m
length = 3*4 = 12m
Breadth = [tex]\frac{3}{2}*4=3*2=6 \ m[/tex]
Area of floor = l*b
= 12 * 6
= 72 m²
Cost of carpeting the floor = 72 * 325 = ₹ 23400
