Suppose y varies inversely with X, and y = 36 when x = 1/12. What inverse variation equation relates x and y?
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a. y= 3x
b. y= 3/x
c. x/3
d. y= x​


Sagot :

Answer:

B

Step-by-step explanation:

We are given that y varies inversely with x. Recall that inverse variation has the form:

[tex]\displaystyle y=\frac{k}{x}[/tex]

Where k is the constant of variation.

We are given that y = 36 when x = 1/12. Thus:

[tex]\displaystyle (36)=\frac{k}{\left({}^{1}\!/\!{}_{12}\right)}[/tex]

Solve for k. Multiply both sides by 1/12:

[tex]\displaystyle k=\frac{1}{12}(36)=3[/tex]

Hence, our equation is:

[tex]\displaystyle y=\frac{3}{x}[/tex]

Our answer is B.