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Find the slope of the line that passes through the points 4 2 and 5 8

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Naǫid
[tex](4,2) \\ x_1=4 \\ y_1=2 \\ \\ (5,8) \\ x_2=5 \\ y_2=8 \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-2}{5-4}=\frac{6}{1}=6[/tex]

The slope is equal to 6.
Konrad509id
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\\\ m=\dfrac{8-2}{5-4}\\ m=\dfrac{6}{1}\\ m=6 [/tex]

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