what is the slope of the line perpendicular to the line through the points (-1,6) and (3,-4)

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XKelvinid XKelvinid · Answer 1

Answer:

The slope of the perpendicular line is 2/5.

Step-by-step explanation:

We want to find the slope of the line that is perpendicular to the line that passes through the points (-1, 6) and (3, -4).

Recall that the slopes of perpendicular lines are negative reciprocals of each other.

Find the slope of the original line:

[tex]\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-4)-(6)}{(3)-(-1)}=\frac{-10}{4}=-\frac{5}{2}[/tex]

The slope of the perpendicular line will be its negative reciprocal.

Thus, the slope of the perpendicular line is 2/5.

Анонимid Анонимid · Answer 2

The slope of the line perpendicular to the line through the points (-1,6) and (3,-4) is -5/2.

We have to find the slope of the line perpendicular to the line through the points (-1,6) and (3,-4).

using the formula;-

m = (y²-y¹) / (x²-x¹)

Where,

plug the value and simplify.

m = ( (-4 ) - 6)/(3 - (- 1)

m = - 10 / 4

m = - 5/2

Hence, The slope of the line perpendicular to the line through the points (-1,6) and (3,-4) is -5/2.