Sagot :
Answer:
[tex]\angle DFE = \angle DFG[/tex]
Step-by-step explanation:
Given
See attachment for complete question
Required
What makes DEF and DGF congruent
We have:
[tex]EF = GF[/tex] --- this is indicated by the single line on both sides
Also:
[tex]DF = DF[/tex] --- both triangle share same side
For SAS to be true;
2 sides and 1 angle must be equal in either triangles
So far, we have:
[tex]EF = GF[/tex] ---- S
[tex]DF = DF[/tex] ---- S
The additional to complete the proof is:
[tex]\angle DFE = \angle DFG[/tex] ---- angle between the above sides
Reflection is a type of rigid transformation which requires the turning of an object, shape or figure about a reference point or line. Therefore, the needed additional information is ∠DFE ≅ ∠ DFG. Option B.
Reflection implies turning the given triangle DEF about its side DF, so as to produce an image with the same dimensions but different orientation.
The required proof by Side-Angle-Side (SAS) implies that the relations will be in respect of two of its sides and their included angle.
So that,
GF ≅ FE (given)
DF is the common side to triangles DEF and DFG.
DFG is the included side.
Thus;
∠DFE ≅ ∠ DFG (Side-Angle-Side postulate, SAS)
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