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One number is 10 less than three times a second number. If their sum is 46, find the larger of the two numbers.

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Answer:

32

Step-by-step explanation:

Number 1 =x

Number 2 =(3x-10)

number 1 + number 2 =46

x+(3x-10)=46

4x=56

x=14

Number 1 =x=14

Number 2=3x-10

                 3(14)-10

                   32

Number 1 (14)+Number 2 (32)=46

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