Please help me i will give brainlest please i need help

Please Help Me I Will Give Brainlest Please I Need Help class=

Sagot :

Answer:

Since you didn't mention which question.

Step-by-step explanation:

13.

[tex]1.\overline{52}\\[/tex] = 1.525252...

Let x = 1.525252...

    10x = 15.2525252....

    100x = 152.525252...

100x - x = 151.00

99x = 151

[tex]x = \frac{151}{99}\\\\or\\\\x = 1 \frac{52}{99}[/tex]

14.

4x + 10 = 8x - 26                        [ corresponding angles are congruent ]

4x - 8x = - 26 - 10

- 4x = - 36

[tex]x = \frac{-36}{-4} \\\\x = 9[/tex]

15.

Given breadth of a rectangle is ( 2/3) its length.

Let the length be x

Therefore, breadth = ( 2 /3) of x

                             [tex]= \frac{2}{3} \times x\\\\=\frac{2}{3}x[/tex]

Given perimeter = 40m

Perimeter of a rectangle = 2( length + breadth)

                                [tex]40 = 2 (x + \frac{2}{3}x )\\\\\frac{40}{2} = \frac{2}{2}(x + \frac{2}{3}x)\\\\20 = x + \frac{2}{3}x\\\\20 = \frac{3x + 2x}{3}\\\\20 \times 3 = 5x \\\\x = \frac{60}{5}\\\\x = 12\\\\Therefore, Length = x = 12 \ m \ and \ breadth = \frac{2}{3}x = \frac{2}{3} \times 12 = 8 \ m[/tex]

16.

Sum of the angles of a triangle = 180°

Given ratio = 2 : 3 : 4

Sum of the ratio = 9

Therefore,

            [tex]first \ angle = \frac{2}{9} \times 180 = 2 \times 20 = 40 ^\circ\\\\Second \ angle = \frac{3}{9} \times 180 = 3 \times 20 = 60^\circ\\\\Third angle = \frac{4}{9} \times 180 = 4 \times 20 = 80^\circ[/tex]

17.

Sum of interior angles of a polygon with n sides = ( n - 2) x 180°

Given polygon is pentagon, that is n = 5

Therefore, sum of the interior angles = ( 5 - 2) x 180 = 3 x 180 = 540°

That is ,

          x + 125 + 125 + 88 + 60 = 540°

          x + 398 = 540°

          x = 540 - 398

          x = 142°

Answer:

Please can you say which question?

Thank you