Sagot :
y = mx + b
4 = m(248) + b
6 = m(372) + b
subtract the two equations to get
-2 = m(-124) + 0
m = 1/62
Then plug in m into one of the equations to find b
4 = (1/62)(248) + b
4 = 4 + b
b = 0
So the equation is
y = (1/62)x + 0
or
y = (1/62)x
or
y = x/62
edit: I totally didn't use point slope. It should be
y + 0 = (1/62)(x + 0)
or y = (1/62)x
(since b is 0, that means she started driving directly at home)
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2) 150mi/1.25hr = Xmi/5hr
750mi/1.25 = X
X = 600miles
4 = m(248) + b
6 = m(372) + b
subtract the two equations to get
-2 = m(-124) + 0
m = 1/62
Then plug in m into one of the equations to find b
4 = (1/62)(248) + b
4 = 4 + b
b = 0
So the equation is
y = (1/62)x + 0
or
y = (1/62)x
or
y = x/62
edit: I totally didn't use point slope. It should be
y + 0 = (1/62)(x + 0)
or y = (1/62)x
(since b is 0, that means she started driving directly at home)
-------------------
2) 150mi/1.25hr = Xmi/5hr
750mi/1.25 = X
X = 600miles
1. the slope formula is rise over run or y2-y1 over/divded by x2-x1 which in your case would be 372-248 over 6-4 so you would write m=y2-y1 over x2-x1 or m=372-248 over 6-4 (please be careful the numbers are small and goes at the bottom of the letter)
2.it would be 600 miles in 5 hours
2.it would be 600 miles in 5 hours