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Given f (x) = x + 1 and g(x) = x^2, what is
( g o f) (x)?

A: ( g o f) (x) = x^2 + 1

B: ( g o f) (x) = (x + 1)^2

C: ( g o f) (x) = x ^ 2 + x + 1

D: ( g o f) (x) = x^2 (x + 1)
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Answer:

Solution given:

f(x) = x +1 and g(x) = x²,

now

(gºf)(x) =g(fx)=g(x+1)=(x+1)²

B) (gºf)(x) = (x + 1)^2

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