Answer:
Given solutions are:
a) 0.1 M of H2S
b) 0.1 M of HNO2
c) 0.1 M of H2SO3
d) 0.1 M of NH4Cl
Explanation:
The electrical conductivity of a solution is directly proportional to the number of ions present in it.
All the given solutions have the same concentration.
But on dissociation, each solution produces a different number of ions as shown below:
[tex]H{2} S ->HS^{-}+H^{+}[/tex]
2 ions per molecule.
[tex]HNO{2} -> H^{+} + NO{2}^{-}[/tex]
2 ions per molecule.
[tex]H2SO3 -> 2H^{+} +SO{3} ^{2-}[/tex]
3 ions per molecule.
[tex]NH{4}Cl -> NH{4}^{+} + Cl^{-}[/tex]
2 ions per molecule.
Answer:
0.1M H2SO3 has high electrical conductivity.
