Sagot :
Answer:
Step-by-step explanation:
for JJ'
x1=-2 x2=3 y1=-2 y2=6
slope =y2-y1/x2-x1
=6-(-2)/3-(-2)
=6+2/3+2
=8/5
for KK'
x1=-8 x2=-3 y1=-4 y2=4
slope=y2-y1/x2-x1
=4-(-4)/-3-(-8)
=4+4/-3+8
=8/5
for LL'
x1=-6 x2=-1 y1=-6 y2=2
slope=y2-y1/x2-x1
=2-(-6)/-1-(-6)
=2+6/-1+6
=8/5
Answer:
Repeat with
(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)
LL' = \sqrt{(-1+6)^2+(2+6)^2}
(−1+6)
2
+(2+6)
2
= \sqrt{5^2+8^2}
5
2
+8
2
= \sqrt{25+64}
25+64
= \sqrt{89}
89