Sagot :
Answer:
x ≥6
Step-by-step explanation:
Given the product:
√(x-6)*√(x+3)
The function has to be defined if x ≥0
Hence;
√(x-6)*√(x+3)≥0
Find the product
√(x-6)(x+3)≥0
Square both sides
(x-6)(x+3)≥0
x-6≥0 and x+3≥0
x≥0+6 and x ≥0 - 3
x ≥6 and x ≥-3
Hence the required inequality is x ≥6