Answer:
The value of time T₁ is 0.323 sec
Explanation:
Given the data in the question;
The inductor will be shorted after a long time;
I = V / R
given that; I = 20.0 A and V = 240 V
we substitute
20 = 240 / R
20R = 240
R = 240 / 20
R = 12 Ohms
Now, when I = 5.00 A
voltage across inductor = 240 - ( 5.0 × 12 )
voltage across inductor = 180 V
so
180 = L × di/dt
given that; increasing at a rate of 20.0 A/s
180 = L × 20
L = 180 / 20
L = 9 H
Now, for the time constant of circuit is T₁
T₁ = L / R = 9 / 12
T₁ = 0.75 s
so
I = l₀( 1 - [tex]e^{(-T/T_1)[/tex] )
we substitute
7.00 = 20.0( 1 - [tex]e^{(-T/0.75)[/tex] )
7/20 = 1 - [tex]e^{(-T/0.75)[/tex]
0.35 = 1 - [tex]e^{(-T/0.75)[/tex]
0.35 - 1 = - [tex]e^{(-T/0.75)[/tex]
-0.65 = - [tex]e^{(-T/0.75)[/tex]
0.65 = [tex]e^{(-T/0.75)[/tex]
ln(0.65) = -T₁ / 0.75
-0.43078 = -T₁ / 0.75
-T₁ = -0.43078 × 0.75
-T₁ = -0.323
T₁ = 0.323 sec
Therefore, The value of time T₁ is 0.323 sec