Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Step-by-step explanation:
Given the data in the question;
Feeder 1 2 3 4
Observed visits; [tex]o_i[/tex] 60 90 92 58
data sample = 300
Expected [tex]e_i[/tex] = 300 / 4 = 75
the x² test statistic = ?
[tex]X^2_{stat[/tex] = ∑[ ([tex]o_i[/tex] - [tex]e_i[/tex])²/[tex]e_i[/tex]]
[tex]X^2_{stat[/tex] = [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
[tex]X^2_{stat[/tex] = [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
[tex]X^2_{stat[/tex] = 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.