Answered

Find three consecutive integers such that 5 times the first decreased by three times the
second is 5 more than the third.

Sagot :

Konrad509id
[tex]5n-3(n+1)=n+2+5\\ 5n-3n-3=n+7\\ 5n-3n-n=7+3\\ n=10\\ n+1=11\\ n+2=12[/tex]

10,11,12