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find x

plz help!!!!!!!!

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Konrad509id
[tex]24+6x\not=0\\ 6x\not=-24\\ x\not=-4\\\\ 9x^2+36x+36=0\\ 9(x^2+4x+4)=0\\ 9(x+2)^2=0\\ \boxed{x=-2}[/tex]
AL2006id
'x' can be anything.  There's no information here to say that it must be
one thing or another. You can't find 'x', because there is no equation.

You can probably simplify the fraction by doing some factoring, but there's
no way to tell a value for 'x'.  As long as 'x' is not -4, it can be anything, and
its value determines the value of the fraction.

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