Sagot :
Answer:
They can be seated in 10,080 ways.
Step-by-step explanation:
Arrangements of n elements:
The number of possible arrangements of n elements is given by:
[tex]A_n = n![/tex]
In this question:
In each end, the two admirals, so 2 possible outcomes.
In the middle seats, arrangements of 7 elements(3 generals, 4 lieutenants). So
[tex]2A_{7} = 2*7! = 10080[/tex]
They can be seated in 10,080 ways.
The number of ways they can be seated is 10,080 ways.
Permutations and combination
The number of possible ways fof arranging n elements is given as:
P = n!
According to the question, there are 2 admirals! 3 generals and 4 lieutenant.
In each end, the two admirals, so 2 possible outcomes.
In the middle seats, arrangements of 7 elements(3 generals, 4 lieutenants). Hence the required number of combination will be given as:
Number of ways = 2*7!
Number of ways = = 100802
Hence the number of ways they can be seated is 10,080 ways.
Learn more on permutations here: https://brainly.com/question/1216161