A 12-volt battery causes 0.60 ampere to flow through a circuit that contains a lamp and a resistor connected in parallel. The lamp is operating at 6.0 watts.
Calculate the resistance of the resistor.

A: 7.2
B: 60
C: 72
D: 120

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Sagot :

Fjnyid Fjnyid · Answer 1

The answer to this question is A

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Vickynehraid Vickynehraid · Answer 2

The resistance of the resistor is 120 Ω

"Resistance is a measure of the opposition to current flow in an electrical circuit."

Data given

Power of lamp (P)= 6 W,

Emf of cell (V)= 12 Volt

Current drawn from cell (i) = 0.6 A

Combination is parallel, it means the potential on resistor and lamp is same, so current taken by lamp, by formula,

P= V .i

Substitute the values,

6 = 12× i

i = [tex]\frac{6}{12}[/tex]

i = 0.5 A ( current taken by lamp) so current taken by resistor,

[tex]i_{r} = 0.6-0.5 =0.1 A[/tex]

Now the resistance of resistor, by formula,

[tex]R = \frac{V}{i_{r} }[/tex]

[tex]R = \frac{12}{0.1} \\R = 120[/tex] Ω

Hence the resistance of the resistor is 120 Ω.

To learn more about resistance here

https://brainly.com/question/17562635

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