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1. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -CH3
b) -CH2OH
c) -CH2NH2
d) -CH2BR2. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -F
b) -CH2OH
c) -CHO
d) -CH3

Sagot :

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Answer:

1. CH₂Br > CH₂OH > CH₂NH₂ > CH₃

2. -F > -CHO > - CH₂OH > CH₃

Explanation:

The arrangement of the above atom is due to their atomicity and electronegativity of the given compounds.

From (1) we will realize that Bromine (Br) possesses the greatest priority because its atomic number is the highest. This is followed by oxygen (O) in CH₂OH since atomic no 8 is higher than that of Nitrogen N(7). Lastly, CH₃ has the only hydrogen attached to it with the atomic no of (1)

In the second part of the question>

The electronegativity of an element increases across the period and down the group. Fluorine is highly electronegative and contains the highest atomic number of oxygen in -CHO. The oxygen (O) in -CHO has a double bond which gives an edge over the (O) in CH₂OH. Lastly, CH₃ contains a substituted hydrogen atom

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