[tex]y=3x-10\\\\
General\ formula:\\y=ax+b\\\\
Line\ is\ perpendicular when\ new\ a=-\frac{1}{a}\\y=-\frac{1}{3}x+b\\\\
Passes\ through\ (-3,6):\\6=-3(-\frac{1}{3})+b\\6=1+b\ \ \ | subtract\ 1\\b=5\\\\
Equation\ for\ line\ is\ y=-\frac{1}{3}+5
[/tex]
