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at Niagara Falls, if 505 kg of water fall a distance of 50.0 m, what is the increase in the internal energy of the water at the bottom of the falls? Assume that all of the initial potential energy goes into increasing the water's internal energy and that the final kinetic energy is zero

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Answer:

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Explanation:

the increase in the internal energy of the water at the bottom of the falls

= mgh

= 505 * 9.81 * 50

= 247703 J ----answer

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