The time at which the distance of both the riders will be same is required.
At 5 minutes they both would have covered 20 miles.
The given lines are [tex]y=4x[/tex] and [tex]y=3x+5[/tex]
So,
[tex]4x=3x+5\\\Rightarrow 4x-3x=5\\\Rightarrow x=5[/tex]
Finding [tex]y[/tex]
[tex]y=4x\\\Rightarrow y=4\times 5=20[/tex]
At [tex]x=15[/tex] the distance covered by both riders is [tex]y=20[/tex]
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