POisenrOseid
Answered

Please try to answer all of them :)
Three shipping companies want to compare the mean numbers of deliveries their drivers complete in a day.
The first two shipping companies provided their data from a sample of drivers in a table.

Company C showed its data in a dot plot.


Answer the questions to compare the mean number of deliveries for the three companies.

1. How many drivers did company C use in its sample?

2. What is the MAD for company C's data? Show your work.

3. Which company had the greatest mean number of deliveries?

4. Compare the means for companies A and B. By how many times the MAD do their means differ? Show your work.

Please Try To Answer All Of Them Three Shipping Companies Want To Compare The Mean Numbers Of Deliveries Their Drivers Complete In A Day The First Two Shipping class=

Sagot :

Raelynndonovan89id

Answer:

Here are #1 threw #3 answers

#1 is 10

# 2 is

6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The (Mean) = 10

(6- 10) + (7- 10) + (8- 10) + (9- 10) + (10- 10) + (10- 10) + (10- 10) + (12- 10) + (14- 10)

4 + 3 + 2 + 1 + 0 + 0 + 0 + 2 + 4

= 16/10 = 1 6/10

The (MAD) = 1 6/10

#3 Groups A & B

#4 sorry I can’t figure this out but I did 1/2/3

Step-by-step explanation:

Nurse0506id

Answer:

1. the company C used 10 drivers2.      6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The Mean = 10  (6- 10) + (7- 10) + (8- 10) + (9- 10) + (10- 10) + (10- 10) + (10- 10) + (12- 10) + (14- 10)4 + 3 + 2 + 1 + 0 + 0 + 0 + 2 + 4  = 16/10 = 1 6/103. The groups that had the most deliveries where group A and B4. So if there are 6 deliveries of group A and 14 deliveries from group B i think the MAD would be 4

Step-by-step explanation:

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