Sagot :
Answer:
See Explanation
Explanation:
moles of NH₃ = 11.9g/17.03 g/mol = 0.699 mole
moles of CN₂OH₄ = 1/2(0.699) mole =0.349 mole
Theoretical yield of CN₂OH₄ = (0.349 mole)(60 g/mole) = 20.963 grams
%Yield = Actual Yield/Theoretical Yield x 100%
= 18.5g/20.963g x 100% = 88.25%
Answer:
same process as last solution I did for you except the mole ratio isn't 1:1 here it is 2:1 so you diveide the moles of NH3 by 2 to get the urea moles
here I got 88.16% yield
Explanation: