Sagot :
1) For the remaining 3 days he plays 1.5 hours of video games per day
2a) h > 20
2b) (15.5x + 50) > 400
2c) x > 22.58
3) x < 11.5 weeks
4) 180 minutes
2a) h > 20
2b) (15.5x + 50) > 400
2c) x > 22.58
3) x < 11.5 weeks
4) 180 minutes
so
1. 10 minus 5 and 1/2 = 4 and 1/2 divide by 3 and get 1 and 1/2 or 3/2 per day
2. there is no graph provided so I cannot solve this part
3. 650-x(50)>75
575-x(50)>0
50(11.5-x)>0
x must be less than 11
4. first is
total cost=0.25m+5
second is
total cost=50
so we put total cost of second less than first so
50>0.25m+5
45>0.25m
180>m
so you can talk less than 180 minutes to spend less than the first option
1. 10 minus 5 and 1/2 = 4 and 1/2 divide by 3 and get 1 and 1/2 or 3/2 per day
2. there is no graph provided so I cannot solve this part
3. 650-x(50)>75
575-x(50)>0
50(11.5-x)>0
x must be less than 11
4. first is
total cost=0.25m+5
second is
total cost=50
so we put total cost of second less than first so
50>0.25m+5
45>0.25m
180>m
so you can talk less than 180 minutes to spend less than the first option