V,? = V2 + 2a Ax
1. A toy car increases velocity over a displacement of 15.2 m. If
the car starts at rest and has a final velocity of 0.76 m/s, what
is the magnitude of its acceleration?


Sagot :

Answer:

Explanation:

[tex]V^2=V^2_i+2a(x_f-x_i)[/tex]

[tex]0.76^2=0^2+2a(15.2)[/tex]

[tex]0.5776=30.4a[/tex]

[tex]a=0.019m/s^2[/tex]