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If two negative charges of -2 C and -2 C are put 32,692 m apart from each other how much force will push them apart?

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Answer:

33.65 N

Explanation:

Force that will push them away is given from the equation;

F = Kq1•q2/r²

Where;

K is coulumbs constant = 8.99 × 10^(9) Nm²/C²

We are given;

q1 = q2 = -2 C

r = 32692 m

Thus;

F = 8.99 × 10^(9) × (-2) × (-2)/32692²

F ≈ 33.65 N

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