Answer:
[tex]m_{C_6H_5Cl}=65.7gC_6H_5Cl[/tex]
Explanation:
Hello!
In this case, according to the given balanced chemical reaction:
[tex]C_6H_6 (l) + Cl_2 (g) \rightarrow C_6H_5Cl (s) + HCl (g)[/tex]
We can see there is 1:1 between benzene and chlorobenzene as the relavant product; thus, since the molar mass of benzene is 78.11 g/mol and that of chlorobenzene is 112.55 g/mol, the theoretical yield for this reaction turns out:
[tex]m_{C_6H_5Cl}=45.6gC_6H_6*\frac{1molC_6H_6}{78.11gC_6H_6 }*\frac{1molC_6H_5Cl}{1molC_6H_6}*\frac{112.55gC_6H_5Cl}{1molC_6H_5Cl} \\\\m_{C_6H_5Cl}=65.7gC_6H_5Cl[/tex]
Best regards!