Sagot :
[tex]a=21 \ m , \ b=28 \ m , \ c=5x \ m \\ \\c^2 =a^2 + b^2\\ \\(5x)^2 =21^2 + 28^2\\ \\25x^2=441+784\\ \\25x^2=1225/:25\\ \\x^2=49\\ \\x=\sqrt{49}\\ \\x=7 \ m[/tex]
The value of x of a triangle that has the legs of lengths 28 meters and 21
meters and the hypotenuse of 5x meters is 7
The triangle is a right angle triangle .
Using Pythagoras theorem, let's find the hypotenuse side and invariably the value of x
c² =a² + b²
(5x)² = 28² + 21²
25x² = 784 + 441
25x² = 1225
square root both sides
5x = √1225
5x = 35
divide both sides by 5
5x / 5 = 35 / 5
x = 7
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