Sagot :
We have to check if LHS = RHS
First solve LHS
[tex] \frac{5}{6}- \frac{3}{4} = \frac{5*2}{6*2}- \frac{3*3}{4*3} = \frac{10}{12}- \frac{9}{12}= \frac{1}{12} So LHS is equal to RHS. [/tex]
First solve LHS
[tex] \frac{5}{6}- \frac{3}{4} = \frac{5*2}{6*2}- \frac{3*3}{4*3} = \frac{10}{12}- \frac{9}{12}= \frac{1}{12} So LHS is equal to RHS. [/tex]