Answer:
0.00265
Step-by-step explanation:
We solve using the z score formula
z = (x-μ)/σ/√n
where
x is the raw score = $25,000
μ is the population mean = $26,489
σ is the population standard deviation = $3204
n = random number of samples = 36
For x < 25,000
z = 25000 - 26489/3204/√36
z = 25000 - 26489/3204/6
z = -1489/534
z = -2.78839
Probability value from Z-Table:
P(x<25000) = 0.0026485
Approximately = 0.00265
The probability that the sample mean cost for these 36 schools is Less than $25,000 is 0.00265