Answer:
2
Explanation:
From the question given above, the following data were obtained:
Molarity of HCl = 0.01 M
pH =?
Next, we shall determine the concentration of the hydrogen ion, [H⁺] in the pool. This can be obtained as follow:
HCl (aq) <=> H⁺ (aq) + Cl¯ (aq)
From the balanced equation above,
1 mole of HCl produced 1 mole of H⁺.
Therefore, 0.01 M HCl will also produce 0.01 M H⁺.
Thus, the concentration of the hydrogen ion, [H⁺] in the pool is 0.01 M
Finally, we shall determine the pH of the pool.
This can be obtained as follow:
Concentration of the hydrogen ion [H⁺] = 0.01 M
pH J?
pH = – Log [H⁺]
pH = – Log 0.01
pH = 2
Therefore, the pH of the pool is 2.
