PLEASE HURRY!!!!!!
If a=-3x-i and b=3, then find the value of the ab^(2)

in fully simplified form.


Sagot :

Answer:

Step-by-step explanation:

a= -3x-i

b= 3

[tex]b^{2}[/tex]=9

sooo..  a[tex]b^{2}[/tex] = (-3x-i )(9)

-27x -9i  

Caveat :     :/  if the i happens to be part of a complex number and the squared part is for the quantity (AB)^2  then it would change this answer ..but... I can't tell if that problem is about complex numbers or not, i'm guessing it's not