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If 13.0g of CO2 gas has a volume of 0.46L at 310K , what is its pressure in millimeters of mercury?

Sagot :

PyroManiacid
pV = nRT ---> p = nRT/V
n = m/M, so:  p = mRT/VM, where:
p - pressure
m - mass of CO2 in grams
R - universal gas constant
T - temperature in K
V - volume in L
M - molar mass of CO2 = 44 g/mol

133.3224 Pa = 1 mm Hg

so i think You can handle this right now.

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