[tex](-3,3)\ \ and\ \ (-6,-2) \\\\ First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ -2-3}{-6+3} = \frac{-5}{-3}=\frac{5}{3} \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point:[/tex]
[tex]y-y_{1} =m(x-x _{1}) \\\\y-3=\frac{5}{3}(x+3)\\\\y=\frac{5}{3} x+5+3\\\\y=\frac{5}{3} x+8[/tex]
