Sagot :
convert this to slope-intercept form
subtract 1/4x,
3/4y=1-1/4x
then multiply my 4/3
y=4/3-1/3x
y=-1/3x+4/3
4/3 is the y-intercept, so when you're graphing begin with it. Then find another point on the graph according to the slope. Plot point (0,4/3) then plot a point with a y-value 1 less and an x-value 3 more. (slope is sometimes called rise over run because it is a ratio of the change in the y-value divided by the change in the x-value) Plot point (3,1/3). Connect the dots with a ruler and draw a line.
subtract 1/4x,
3/4y=1-1/4x
then multiply my 4/3
y=4/3-1/3x
y=-1/3x+4/3
4/3 is the y-intercept, so when you're graphing begin with it. Then find another point on the graph according to the slope. Plot point (0,4/3) then plot a point with a y-value 1 less and an x-value 3 more. (slope is sometimes called rise over run because it is a ratio of the change in the y-value divided by the change in the x-value) Plot point (3,1/3). Connect the dots with a ruler and draw a line.
[tex]standard \ linear \ equation\ :\\\\y=ax+b\\\\ \frac{1}{4}x + \frac{3}{4} y = 1 \ \ | \ multiply \ each \ term \ by \ 4\\ \\ x+3y=4 \ \ |\ subtract x\ to\ both\ sides\\\\3y=-x+4\ \ | \ divide \ each \ term \ by \ 3\\\\y=-\frac{1}{3}x+ \frac{4}{3}[/tex]