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how to factor 64x^4 + xy^3

Sagot :

you factor out an x and get
x(64x^3+y^3)
Apologiabiologyid
so we kkonw that 64=4^3
so if we factor out x we get
x(4^3(x^3)+y^3) or x[(4x)^3+y^3)
so the additon of two perfect cubes so

(4x+y)(16x^2+4xy+y^2)
and we remember that this is all times x so
x[(4x+y(16^2+4xy+y^2))]
 or (x)(4x+y)(16x^2+4xy+y^2)