Andreahuff1973id
Andreahuff1973id
Mathematics
Answered
How to
Simplify 243^1.2
Sagot :
Анонимid
Анонимid
[tex]243^{1,2}=243^{1\frac{2}{10}}=243^{1\frac{1}{5}}=243^{1+\frac{1}{5}}=243^1\cdot243^\frac{1}{5}=243\sqrt[5]{243}\\\\=243\sqrt[5]{3^5}=243\cdot3=729[/tex]
Answer Link
Zidanethernandez8id
Zidanethernandez8id
Answer:729
Step-by-step explanation:
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