Answered

what is the equation of a circle with center (2, -5) and radius 4?

Sagot :

Luanaid
[tex]Equation\ of\ circle\\\\\ r^2=(x-a)^2+(y-b)^2\\\\ a,b- \ coordinates\ of\ center\ of\ circle\\\\\ (a,b)=(2,-5) \\\\ r-\ radius\\\\ r=4\\\\Solution:\ 4^2=(x-2)^2+(y+5)^2\\\\\ [/tex]
Konrad509id
[tex](x-h)^2+(y-k)^2=r^2\\\\ (x-2)^2+(y+5)^2=16[/tex]