Sagot :
[tex]2x^2-5x-3=0\ \ \ \ | write\ -5x\ as\ -6x+x\\\\ 2x^2-6x+x-3=0\\\\
x(2x+1)-3(2x+1)=0\\\\
(x-3)(2x+1)=0\\\\
x=3\ \ or\ \ 2x=-1\\\\
x=3\ \ \ or\ \ \ x=-\frac{1}{2}[/tex]
the factors of 2 are one and two... the factors of -3 are negative 3 and 1. (2X-1)(X-3)