The possible values of [tex]x[/tex] for [tex]2\cdot x^{2}+6\cdot x = 36[/tex] are [tex]x_{1} = 3[/tex] and [tex]x_{2} = -6[/tex].
The expression [tex]2\cdot x^{2}+6\cdot x = 36[/tex] is equivalent to the expression [tex]2\cdot x^{2}+6\cdot x -36 = 0[/tex], which represents a second order polynomial, that is, a polynomial of the form:
[tex]y = a\cdot x^{2}+b\cdot x + c[/tex] (1)
Where [tex]a,\,b,\,c[/tex] are coefficients.
The possible values of x represents all possible roots of x, which are found analytically by the quadratic formula:
[tex]x = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex] (2)
If we know that [tex]a = 2[/tex], [tex]b = 6[/tex] and [tex]c = -36[/tex], then all possible values of [tex]x[/tex] are, respectively:
[tex]x_{1} = 3[/tex], [tex]x_{2} = -6[/tex]
The possible values of [tex]x[/tex] for [tex]2\cdot x^{2}+6\cdot x = 36[/tex] are [tex]x_{1} = 3[/tex] and [tex]x_{2} = -6[/tex].
We kindly invite to check this question on second order polynomials: https://brainly.com/question/24356198
