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how do you prove (3x+2)2 is equivalent to (3x+6)(3x-2)+16

i have tried expanding the brackets but I'm still really stuck
thankyou in advance

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Konrad509id
[tex] (3x+2)^2=9x^2+12x+4\\\\ (3x+6)(3x-2)+16=\\ 9x^2-6x+18x-12+16=\\ 9x^2+12x+4 [/tex]

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